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6 July, 01:11

What is the area of the largest rectangle with lower base on the x-axis and upper vertices on the curve y=12-x^2?

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  1. 6 July, 03:15
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    Area of rectangle: LxW

    so

    (2x) (y) = 2x (12-X^2)

    then I would solve for x and substitute it back into the Area equation.

    This is your area equation:

    A = 2x (12-x^2)

    maximize by differentiating and setting equal to 0 then solve for x.
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