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8 July, 17:25

How to solve 3 sin^ (2) x = cos^ (2) x

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  1. 8 July, 19:51
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    3sin² (x) = cos² (x)

    cos² (x) cos² (x)

    3tan² (x) = 1

    3 3

    tan² (x) = ¹/₃

    tan (x) = ¹/₃√3

    tan⁻¹[tan (x) ] = tan⁻¹ (¹/₃√3)

    x = 30°, 150°

    x = ¹/₆π radians, ⁵/₆π radians
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