Find the equation of the line passing through (-7,-9) and perpendicular to 8x-9y + 2=0

8x - 9y + 2 = 0

-9y = - 8x - 2

y = 8/9x + 2/9 ... the slope here is 8/9. A perpendicular line will have a negative reciprocal slope. All that means is " flip " the slope and change the sign. So our perpendicular line will need a slope of - 9/8 (see how I flipped the slope and changed the sign)

y = mx + b

slope (m) = - 9/8

(-7,-9) ... x = - 7 and y = - 9

now we sub and find b, the y int

-9 = (-9/8) (-7) + b

-9 = 63/8 + b

-9 - 63/8 = b

-72/8 - 63/8 = b

-135/8 = b

so ur perpendicular equation is : y = - 9/8x - 135/8