6x^3 + 9x^2 + 2x + 3 factor thos expression with work?

Split it up an group with like ones (6x^3 with 2x since 6 and 2 are divisble by 2 and 9x^2 with 3 since both divisible by 3)

(6x^3+2x) + (9x^2+3)

undistribute using reverse distributive property (ab+ac=a (b+c))

2x (3x^2+1) + 3 (x^2+1)

undistribute again

(3x^2+1) (2x+3)