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7 August, 05:54

If 12^x2+^5x-4=12^2x+6, what could be the value of x?

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  1. 7 August, 06:37
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    Since the both have the same base 12 you can write like thus

    X^2+5x-4=2x+6

    X^2+5x-4-2x-6=0

    X^2+3x-10=0

    (X-2) (X+5)

    X-2=0. X+5=0

    X=2. And X=-5
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