1. An acute angle _ is in a right triangle with cos _ = (5) / (6). What is the value of sec _?

2. An acute angle _ is in a right triangle with sin _ = (5) / (6). What is the value of cot _?"

Question

Mathematics

Lilah Snyder

18 October, 14:08

1. An acute angle _ is in a right triangle with cos _ = (5) / (6). What is the value of sec _?

2. An acute angle _ is in a right triangle with sin _ = (5) / (6). What is the value of cot _?"

+1

Answers (1)

Know the Answer?

Cason Meyer · Answer 1

1)

Cosine = base / hypotenuse

Secant = hypotenuse / base = 1/Cosine

Sec = 1 / (5/6) = 6/5

2)

Sine = perpendicular / hypotenuse = 5/6

hypotenuse² = base² + perpendicular²

base = √ (6² - 5²)

base = √11

Cotangent = base / perpendicular

= √11/5

1. An acute angle _ is in a right triangle with cos _ = (5) / (6). What is the value of sec _?2. An acute angle _ is in a right triangle with sin _ = (5) / (6). What is the value of cot _?"

1. An acute angle _ is in a right triangle with cos _ = (5) / (6). What is the value of sec _?

2. An acute angle _ is in a right triangle with sin _ = (5) / (6). What is the value of cot _?"