C=0.04x^2-8.504x+25302 how do i do this?

Solving for x.

Since x is on the right-hand side of the equation, switch the sides so it is on the left-hand side of the equation.

0.04 x2 - 8.504x+25302=c

Simplify the quadratic and set the right side equal to 0.

0.04 x2 - 8.504x+25302-c=0

Use the standard form of the quadratic (a x2 + bx+c) to find a, b, and c for this quadratic.

a=0.04, b=-8.504, c=25302-1c

Use the quadratic formula to find the solutions.

x = - b ± √ b2 - 4ac / 2a

Substitute in the values of a=0.04, b=-8.504, and c=25302-1c.

x = - (-8.504) ± √ (-8.504) 2 - 4 (0.04) (25302-1c) / 2 (0.04)

Simplify.

x = 8.504 ± √ (-8.504) 2 - 4 (0.04) (25302-1c) / 2 (0.04)

Simplify the section inside the radical.

x = 8.504 ± √ - 3976.001984+0.16c / 2 (0.04)

Simplify the denominator of the quadratic formula.

x = 8.504 ± √ - 3976.001984+0.16c / 0.08

Answer:

x=8.504 ±√-3976.001984+0.16c/0.08