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2 January, 06:05

X⁴+5x²-6=0 solve for x

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  1. 2 January, 08:29
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    Let u = x², then we would have u² + 5u - 6 = 0

    From here, we can factor it and get us (u-1) (u+6) = 0

    So our solution for u is u = - 6 or 1.

    Now substitute u back to x².

    x² = - 6 or 1

    x = ±√ (-6) or ±√1

    Since ±√ (-6) is not real number, we ignore it.

    Which leave us x = ±√1 = ±1

    So our real solution is x = - 1 or 1.
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