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11 September, 15:06

The expression 3x^2-33x-180 can be factored into the form a (x+b) (x+c) where a, b, and c are constants, to reveal the zeros of the function defined by the expression. What are the zeros of the function defined by 3x^2-33x-130? Select all that apply

a) - 15

b) - 10

c) - 6

d) - 4

e) 4

f) 6

g) 10

h) 15

+3
Answers (1)
  1. 11 September, 17:07
    0
    3x²-33x-180=3 (x²-11x-60) = 3 (x-15) (x+4)

    the roots are when x-15=0, x=15 and when x+4=0, x=-4

    d and h are the answers.
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