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13 September, 15:22

Prove the following equation: sin (90 + theta) = cos theta ...

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  1. 13 September, 18:28
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    To prove this kind of equation you must use the Trigonometric Function of Equality. And came up with the formula of sin (x+y) = sin (x) * cos (y) + cos (x) * sin (y) and then substitute the variables that is present if your function and came up with an answer of sin (90-theta) = sin (90) * cos (theta) + cos (90) * sin (theta) = cos (theta)

    I hope i answered your question
  2. 13 September, 19:01
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    Using the trigonometric equality:

    sin (x+y) = sin (x) * cos (y) + cos (x) * sin (y)

    then:

    sin (90+θ) = sin (90) * cos (θ) + cos (90) * sin (θ) = cos (θ)
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