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11 January, 03:23

Factor by completing the square 5x^2-21=10x

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  1. 11 January, 06:19
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    Solve for x over the real numbers:

    5 x^2 - 21 = 10 x

    Subtract 10 x from both sides:

    5 x^2 - 10 x - 21 = 0

    Divide both sides by 5:

    x^2 - 2 x - 21/5 = 0

    Add 21/5 to both sides:

    x^2 - 2 x = 21/5

    Add 1 to both sides:

    x^2 - 2 x + 1 = 26/5

    Write the left hand side as a square:

    (x - 1) ^2 = 26/5

    Take the square root of both sides:

    x - 1 = sqrt (26/5) or x - 1 = - sqrt (26/5)

    Add 1 to both sides:

    x = 1 + sqrt (26/5) or x - 1 = - sqrt (26/5)

    Add 1 to both sides:

    Answer: x = 1 + sqrt (26/5) or x = 1 - sqrt (26/5)
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