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21 April, 08:01

Another e integration: xe^ (-x^2)

x times e to the negative x squared

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Answers (1)
  1. 21 April, 11:29
    0
    +∞

    ∫ x · e ^ (-x²) dx = / The substitution: u = - x², x d x = - du / 2

    -∞

    +∞

    = - 1/2 · ∫ e ^ (u) du = - 1/2 · e ^ (-x²) /

    - ∞

    e^ (-∞) = 1 / e^ (∞)

    = - 1/2 · [ 1 / e^ (∞) - 1 / e^ (∞) ] = - 1/2 · (0 - 0) = 0
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