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18 February, 22:20

Find 3 consecutive positive integers such that the product of the first and third integers is 48. Solve algebraically.

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  1. 18 February, 22:58
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    Let integers be x, x+1 and x+2

    x (x + 2) = 48

    x^2 + 2x - 48 = 0

    (x + 8) (x - 6) = 0

    x = 6 (because the integrs are positive

    so the 3 numbers are 6,7 and 8.
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