Three students gambled with the amount of 7:6:5 and finished with sums in the ratio 1:4:7. if one of them lost $22, then what would the total amount at the start of the game be?

Question

Mathematics

Broderick Hardy

11 June, 06:00

Three students gambled with the amount of 7:6:5 and finished with sums in the ratio 1:4:7. if one of them lost $22, then what would the total amount at the start of the game be?

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Ozzy · Answer 1

Make the ratios have a common "total."

7:6:5 is the start

change 1:4:7 to 1.5:6:10.5 so that there are 18 parts.

the only person who lost, lost 5.5 parts which is $22

each part is $4

there are 18 parts, they started out with $72