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6 November, 19:15

If x=-2 is a solution of the equation x^2+bx+6=0 what is the value of b

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  1. 6 November, 21:36
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    u know x = - 2

    x²+bx+6=0

    (-2) ²+b (-2) + 6 = 0

    4 - 2b + 6 = 0

    -2b + 6+4 = 0

    -2 b = - 10

    b = - 10/-2

    b = 5
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