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31 October, 14:26

Rewrite f (x) = x^2+6x-12 in vertex form, then state its vertex and axis of symmetry

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  1. 31 October, 15:27
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    Complete teh square

    isolate x terms

    y = (x^2+6x) - 12

    take 1/2 of 6 and squaer it then add positive and negative inside parenthasees

    6/2=3, 3^2-9

    y = (x^2+6x+9-9) - 12

    comlete the square

    y = ((x+3) ^2-9) - 12

    y = (x+3) ^2-9-12

    y = (x+3) ^2-21

    for

    y = (x-h) ^2+k

    vertex is (h, k)

    axis of symmetry is x=h

    given

    y = (x - (-3)) ^2 + (-21)

    vertex is (-3,-21)

    axis of symmetry is x=-3
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