2. Solve the following system of equations using substitution.

2x+2y=38

Y=x+3

A. (8,11)

B. (4,7)

C. (35/4, 47/4)

D. (-4,-7)

First, make sure you convert both equations into standard form. Your two equations would be 2x+2y=38 and - x+y=3. Then multiply the bottom by 2. So your new equations would be 2x+2y=38 and - 2x+2y=6. The x would cancel out and you would continue solving for y. y would equal 11 and then you would plug it back into an original equation. When you plug and solve for x, you would get x=8. So your answer would be (8,11)