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30 January, 16:43

A trapeziodal pyramid has a volume 2856insquared the height of the pyramid is 24in and the lengths of the 2 two bases of the trapeziodal base are 13 and 29 in what is the height of the trapeziodal base

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  1. 30 January, 20:35
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    V = 1/3Bh

    B = 1/2 (b1 + b2) t

    V = 1/3[1/2 (b1 + b2) t] * h

    h = 24

    b1 = 13

    b2 = 29

    t = ?

    V = 2856

    Substitute:

    2856 = 1/3[1/2 (13 + 29) t] (24)

    2856 = 1/6 (42) (24) t

    2856 = 7 (24) t

    2856 = 168t

    t = 2856/168 = 17 in height of the trapeziod
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