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9 December, 03:09

Jen knows that (-1, 41) and (5, 41) lie on a parabola defined by the equation y=4x^2-16x+21. How can I find the coordinates of the vertex?

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  1. 9 December, 03:31
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    The vertex is at (2, 5).

    To find the vertex, we first find the axis of symmetry; this is given by

    x = - b/2a

    For our equation, b = - 16 and a = 4:

    x = - (-16) / 2 (4) = 16/8 = 2

    We substitute this back into our equation:

    y = 4 (2) ² - 16 (2) + 21 = 4 (4) - 32 + 21 = 5

    Therefore the vertex is at (2, 5).
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