What is the vertex and y-intercept of f (x) = - 2x^2 + 4x + 6

F (x) = - 2x^2+4x+6

We can use - b/2a to find the line of symmetry

a = - 2

b = 4

c = 6

and the x value for the line of symmetry gives you the x value for the vertex

-4 / (2*-2)

-1=x

Plug this x value back into the function to find the y value for the vertex

f (x) = - 2 (-1) ^2 + (4*-1) + 6

f (x) = - 2 + (-4) + 6

f (x) = 0

the c value is the y intercept

Vertex: (-1,0)

Y intercept: 6