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Mathematics
Samuel
13 March, 14:27
Expand the following: 1/3 (6/5x-3)
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Brooks Mclaughlin
13 March, 17:56
0
x in (-oo:+oo)
(1/3) * ((6/5) * x-3) = 0
1/3 * (6/5*x-3) = 0
(1/3)
1/3 = 0
x belongs to the empty set
(6/5*x-3)
6/5*x-3 = 0 / / + 3
6/5*x = 3 / / : 6/5
x = 3/6/5
x = 5/2
x = 5/2
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