The length of a rectangle is twice the width. if the perimeter of the rectangle is 24, what is the area of the rectangle?

Let L be length and W be width.

L = 2W

And our perimeter is 2L + 2W. Substitute L to get:

2 * (2W) + 2W = 24

4W + 2W = 24

6W = 24

W = 4

That means L equals 8.

So our area of the rectangle is L*W or 8*4 = 32 units squared