To the nearest tenth of a degree, find the sizes of the acute angles in the 7-24-25 right

triangle and in the 8-15-17 right triangle. This information then allows you to calculate

the sizes of all the angles in the 25-51-52 triangle.

First of all, just to avoid being snookered by a trick question, we should verify that these are really right triangles:

7² + 24² really is 25², and 8² + 15² really is 17², so we're OK there.

In the first one:

sin (one acute angle) = 7/25 = 0.28

the angle = sin⁻¹ (0.28) = 16.26°

the other acute angle = (90° - 16.26°) = 73.74°

In the second one:

sin (one acute angle) = 8/17 = 0.4706 ...

the angle = sin⁻¹ (0.4706 ...) = 28.07°

the other acute angle = (90° - 28.07°) = 61.93°

I'm sorry, but just now, I don't know how to do the

third triangle in the question.