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Mathematics
Delaney Marquez
2 August, 21:03
Solve x^2-y=-2
-x+y=4 using the elimination method
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Ronald Hammond
3 August, 00:42
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X² - y = - 2 ... equation 1
-x + y = 4 ... equation 2 from the y's we can obtain y - y = 0
the new equation will be
x² - x = 2 to for a quadratic equation make the equation equals to zero
x² - x - 2 = 0
x² - 2x + x - 2 = 0 using factorization method
x (x - 2) + 1 (x - 2) = 0
(x + 1) (x - 2) = 0
x + 1=0 and x - 2=0
x = - 1 or 2
subtitute x = - 1 in equation 2 subtitute x = 2 in equation 2
- (-1) + y = 4 - (2) + y = 4
1 + y = 4 - 2 + y = 4
y = 4 - 1 y = 4 + 2
y = 3 y = 6
the values of x are - 1 and 2. The values of y are 3 and 6
when x is - 1, y is 3
when x is 2, y is 6 ...
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