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1 January, 15:57

Derivative of sec^2 (x? it equals 2*sec^2 (x*tan (x but why doesn't the ^2 part disappear? the derivative of sin^2 (x = 2sinxcosx so i thought the ^2 part would disappear in the derivative of sec^2 (x ...

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  1. 1 January, 19:24
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    Y = sec^2 x

    use the product rule

    dy/dx = sec x * sec x tan x + sec x tan x sec x

    = 2 sec^2 tan x
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