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22 January, 16:59

The vertices of triangle QPR are Q (-4,0), P (-6, 7), and R (-2, 1). / is rotated 90° counterclockwise about the origin to form Q' P' R'. What are the coordinates of the vertices of Q'P'R'?

A. Q' (0, - 4), P' (-7, - 6), R' (-1, - 2)

B. Q' (0, - 4), P' (7, 6), R' (1, - 2)

C. Q' (0, 4), P' (-7, 6), R' (-1, 2)

D. Q' (4, 0), P' (6, 7), R' (2, - 1)

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Answers (1)
  1. 22 January, 17:46
    0
    I'm pretty sure the answer would be A.
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