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6 November, 19:38

5 consecutive intergers whose sum is 195

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  1. 6 November, 21:06
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    X + (x+1) + (x+2) + (x+3) + (x+4) = 195

    5x + 10 = 195

    5 (x+2) = 195

    x + 2 = 39

    x = 37

    The 5 consecutive integers whose sum is 195 are 37, 38, 39, 40, 41.
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