What is the 12th term of the arithmetic sequence where a1 = 5 and a6 = 20?

An=a1+d (n-1)

an=nth term

a1=first term

d=common differnce

n=which term

alrighty, a1=5

neat

an=5+d (n-1)

given a6=20

20=a6=5+d (6-1)

20=5+d (5)

20=5+5d

minus 5 both sides

15=5d

divide both sides by 5

3=d

so

an=5+3 (n-1) is the formula for the nth term

12th term

a12=5+3 (12-1)

a12=5+3 (11)

a12=5+33

a12=38

the 12th term is 38