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Mathematics
Izabelle Walsh
27 October, 08:14
Solve e ^ - x^2 = 0.23
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Winston Hanson
27 October, 11:44
0
If e repersents the something of logarithms then
I memorised e to 16 digits:2.718281828459045 ...
so that number^2-x^2=0.23
number squred=aprox 7.38906
7.38906-x^2=0.23
subtract 7.38906 forom both sides
-x^2=-7.15906
multiply negative
x^2=7.15906
squre root
2.67564=x
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