Find the horizontal asymptote of f (x) = x^2+6x-8/x-8

Question

Mathematics

Zion Combs

29 November, 21:17

Find the horizontal asymptote of f (x) = x^2+6x-8/x-8

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Answers (2)

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Chicken Wing · Answer 1

Chicken Wing 29 November, 22:54

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Look at the definitiioin

Yair Zuniga · Answer 2

1. If nm n>m, then there is no horizontal asymptote (there is an oblique asymptote). x2 - 6 x + 8 x2 - x - 12 x2 - 6 x + 8 x2 - x - 12 Find nn and mm. n=2 n=2 m=2 m=2 Since n=m n=m, the horizontal asymptote is the line y = ab y = ab where a=1 a=1 and b=1 b=1. y=1 y=1 There is no oblique asymptote because the degree of the numerator is less than or equal to the degree of the denominator. No Oblique AsymptotesThis is the set of all asymptotes. Vertical Asymptotes: x = - 3 x = - 3 Horizontal Asymptotes: y = 1