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29 November, 12:03

What are the zeros of the function f (x) = (3x^2 + 9x + 6) / (3x - 6) ?

-1

1

2

-2

+5
Answers (1)
  1. 29 November, 13:00
    0
    3x^2 + 9x + 6 = 0

    3x^2 + 3x + 6x + 6 = 0

    3x (x + 1) + 6 (x + 1) = 0

    (3x + 6) (x + 1) = 0

    3x + 6 = 0 and x + 1 = 0

    3x = - 6 and x = - 1

    x = - 2 and x = - 1
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