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28 June, 06:00

How to solve 16x to the 4th power y to the 3rd power divided by 2x to the 4th power?

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  1. 28 June, 09:23
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    (16 (x^4) y^3/2x^4 = 8y^3

    Divide 16 by 2, the x^4's cancel leaving 8y^3
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