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26 December, 09:06

Solve:

sin (2x) = sqrt (3) / 2

I

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Answers (1)
  1. 26 December, 10:57
    0
    In order to solve this you will need to use inverse sin function like this:

    sin^-1 ((-sqrt3) / 2) = 2x

    sin^-1 ((-sqrt3/2) = 5pi/3

    5pi/3 = 2x

    (5pi/3) / 2

    5pi/6

    is the answer.

    I hope this goes good
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