A painter leans a 34-ft ladder against a building. The base of the ladder is 16 ft from the building. To the nearest foot, how high on the building does the ladder reach?

Question

Mathematics

Bo Hull

28 August, 17:36

A painter leans a 34-ft ladder against a building. The base of the ladder is 16 ft from the building. To the nearest foot, how high on the building does the ladder reach?

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Woodward · Answer 1

First you need the equation a^2+b^2=c^2. So your new equation is a^2+16^2=34^2. Since 34^2 equals to 1156 and 16^2 equals to 256. You subtract 256 from 1156 which is 900. Since the square root of 900 is 30, the ladder reaches 30 feet high.