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28 August, 17:36

A painter leans a 34-ft ladder against a building. The base of the ladder is 16 ft from the building. To the nearest foot, how high on the building does the ladder reach?

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  1. 28 August, 19:34
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    First you need the equation a^2+b^2=c^2. So your new equation is a^2+16^2=34^2. Since 34^2 equals to 1156 and 16^2 equals to 256. You subtract 256 from 1156 which is 900. Since the square root of 900 is 30, the ladder reaches 30 feet high.
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