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10 May, 23:33

Find three consecutive even integers such that their sum is 50 more than the largest integer

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  1. 11 May, 00:45
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    This is how I'd solve it:

    1st no. = 2x (2x) + (2x+2) + (2x+4) = (2x+4) + 50

    2nd no. = 2x+2 6x+6=2x+54

    3rd no. = 2x+4 4x=48

    x=12

    Substitute the x value, and your numbers are 24, 26, and 28. To check: their sum (78) is 50 more than the largest integer (28).
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