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12 October, 12:34

The area of the region under the curve of the function f (x) = 5x + 7 on the interval [1, b] is 88 square units, where b > 1.

What is the value of b?

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  1. 12 October, 16:14
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    We are given the area of the region under the curve of the function f (x) = 5x + 7 with an interval [1, b] which is 88 square units where b > 1

    We need to find the integral of the function f (x) = 5x + 7 with the limits 1 and b

    5/2 x^2 + 7x (limits: 1, b)

    substitute the limits:

    5/2 (1^2) + 7 (1) - 5/2 b^2 + 7b = 0

    solve for b

    Then after solving for b, this would be your interval input with 1: [1, b].
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