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30 March, 20:56

Find the radius of the circle defined by the equation x^2+y^2+6^x-4y+4=0

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  1. 30 March, 22:44
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    X² + y² + 6x - 4y + 4 = 0

    x² + 6x + y² - 4y + 4 = 0

    x² + 6x + y² - 4y = 4

    (x² + 6x + 9) + (y² - 4y + 4) = 4

    (x + 3) ² + (y - 2) ² = 4

    center: (-3 2)

    radius: 2
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