Cone height is 6 inches and 4 inches diameter. what is the surface area of this container, in square inches?

S = πr (r + √ (h² + r²))

S = (3.14) (2) (2 + √ ((6) ² + (2) ²))

S = 6.28 (2 + √ (36 + 4))

S = 6.28 (2 + √ (40))

S = 6.28 (2 + 2√ (10))

S = 6.28 (2) + 6.28 (2√ (10))

S = 12.56 + 12.56√ (10)

S = 12.56 + 12.56 (3.2)

S = 12.56 + 40.192

S = 52.752