How do I find the factor of the trinomial of y^2+7y-30

Find two numbers that multiply to - 30 (last term) and add to 7 (middle coefficient)

The two numbers are 10 and - 3

10 times - 3 = - 30

10 plus - 3 = 7

Using those two values gets us the two factors (y+10) and (y-3)

Therefore, y^2+7y-30 factors to (y+10) (y-3)

The equation y^2+7y-30 = (y+10) (y-3) is true for all values of y.