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4 August, 06:50

What are the real zeros of x3 + 4x2 - 9x - 36?

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  1. 4 August, 07:57
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    X3 + 4x2 - 9x - 36

    [x3 + 4x2] - 9 [ x+4]

    take x2 common factor from first praket

    x2[x+4] - 9 [x+4]

    = [x+4] * [x2 - 9]

    so the zeros of this equation are - 4, 3, - 3
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