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21 July, 04:46

Using the discriminat, determine the number and type of solutions for this equation : 2x^2 - 3x+1=0

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  1. 21 July, 06:27
    0
    2x² - 3x + 1 = 0

    x = - (-3) ± √ ((-3) ² - 4 (2) (1))

    2 (2)

    x = 3 ± √ (9 - 8)

    4

    x = 3 ± √ (1)

    4

    x = 3 ± 1

    4

    x = 3 + 1 U x = 3 - 1

    4 4

    x = 4 U x = 2

    4 4

    x = 1 U x = ¹/₂

    The solution is {1, ¹/₂}.
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