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18 October, 06:59

A group of 18 people have gotten together to play baseball. they will divide themselves into two teams of 9 players each, with one team wearing green uniforms and the other wearing yellow uniforms. in how many ways can this be done?

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  1. 18 October, 10:47
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    In this problem, what we can do to solve for the number of ways is to use the combination formula:

    nCr = n! / r! (n - r) !

    where n is the total number of people and r is the number of person per team.

    We can identify two cases in this problem.

    1st case: We select the first 9 people for the green team, and the rest of 9 automatically gets to the yellow team therefore the selection is only made on the green team, so

    18C9 = 18! / 9! (18 - 9) ! = 48,620

    2nd case: We select the first 9 people for the yellow team, and the rest of 9 automatically gets to the green team therefore the selection is only made on the yellow team, so

    18C9 = 18! / 9! (18 - 9) ! = 48,620

    The total combination is the sum of the two:

    total number of ways = 48,620 + 48,620

    total number of ways = 97,240
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