Solve.

x/x-2+x-1/x+1=-1

Hello,

We suppose x≠2 and x≠1.

x / (x-2) + (x-1) (x+1) = - 1

==> (x²+x - (x²-x-2x+2)) / (x²-x-2) = - 1

==>4x-2=-x²+x+2

==>x²+3x-4=0

==> (x+4) (x-1) = 0

Sol = {-4,1} which are different of the excluded values.