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6 January, 20:38

Match the functions to the ranges when the domain is (1,2) ... f (x) = 3x + 5 F (x) = x^2 - 2x - 5 F (x) = (x+5) x^2 F (x) = 4-x

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  1. 6 January, 23:41
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    Dommain is input

    range is output from given input (domain)

    1,2

    just input 1 for x and evaluate

    then input 2 for x and evaluate

    f (x) = 3x

    f (1) = 3 (1) = 3

    f (2) = 3 (2) = 6

    range = (3,6)

    f (x) = x^2-2x-5

    f (1) = 1^2-2 (1) - 5=1-2-5=-6

    f (2) = 2^2-2 (2) - 5=-5

    range = (-6,-5)

    f (x) = (x+5) x^2

    f (1) = (1+5) (1^2) = (6) (1) = 6

    f (2) = (2+5) (2^2) = (7) (4) = 28

    range = (6,28)

    f (x) = 4-x

    f (1) = 4-1=3

    f (2) = 4-2=2

    range = (3,2)
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