What is the area between the circles of x^2+y^2=36 and (x-1) ^2 + (y-2) ^2=4

In order to solve this problem, the primary equation to be used in this problem is the formula of the area of the circle which is A = pi r^2 where pi is a constant and r is the radius of the circle. The standard form of a circle is (x-h) ^2 + (y-k) ^2 = r^2 where (h, k) is the center of the circle and r is the radius of the circle. In this case,

1) first circle

x^2 + y^2 = 36

that is (h, k) is at (0,0) and r = 6

2) second circle

(x-1) ^2 + (y-2) ^2=4

that is (h, k) is at (1,2) and r = 2

The area of the first circle is A1 = pi * 6^2 = 36pi while A2 = pi * 2^2 = 4 pi

The difference of the two is equal to 32 pi or equal specifically to 100.48 units^2