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31 July, 02:58

Determine the equation of the inverse of y = 4^ (2x+9)

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  1. 31 July, 05:12
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    Y = 1/2[ (logx/log 4) - 9] is the inverse.

    You can solve this by switching the x and y values and then solve. You'll need to use logarithmic functions in order to get the exponents down.

    x = 4^ (2y+9) - - - > take logs of both sides and move exponents

    logx = (2y + 9) log 4 - - - > divide by log4

    logx/log4 = 2y + 9 - - - > subtract 9

    (logx/log4) - 9 = 2y - - - > multiply by 1/2

    1/2[ (logx/log4) - 9] = y
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