5x^2 + 100=0

a. + - 2 sq rt 5

b. + - 10 sq rt 5

c. + - 2i sq rt 5

d. + - 10i sq rt 5

Question

Mathematics

Mira Short

17 April, 07:27

5x^2 + 100=0

a. + - 2 sq rt 5

b. + - 10 sq rt 5

c. + - 2i sq rt 5

d. + - 10i sq rt 5

+2

Answers (2)

Know the Answer?

Marianna Haney · Answer 1

5 x^2 + 100 = 0

5x^2 = - 100

x^2 = - 100/5

x^2 = - 20

x = + / - sqrt ( - 20)

x = + / - sqrt (-1 * 20))

x = + / - sqrt (-1) * sqrt (20)

x = + / - i * sqrt (4 * 5)

x = + / - 2i sqrt (5)

Answer: Option C

Jase Glover · Answer 2

5x^2+100=0

assuming to salve for x

isolate the x term

subtract 100 from both sides

5x^2=-100

divide both sides by 5

x^2=-100/5=-20

square root both sides

x=√-1 times √4 times √5=i times + / - 2 times √5

i=√-1

the answer is x=-2i√5 or + 2i√5

5x^2 + 100=0a. + - 2 sq rt 5b. + - 10 sq rt 5c. + - 2i sq rt 5d. + - 10i sq rt 5

5x^2 + 100=0

a. + - 2 sq rt 5

b. + - 10 sq rt 5

c. + - 2i sq rt 5

d. + - 10i sq rt 5