A train leaves a train station at 1 pm. It travels at speed of 60 mph. Another train leaves the same station an hour later and goes the same direction at a speed of 80 mph. In how many hours will the second train catch up with the first train?

Relationship between distance-velocity-time as following

d = vt

The second train will catch up on the same distance as the first train.

d₁ = d₂

The first train left one hour before the the second train, that means the first time has an hour more in running time.

t₁ = t₂ + 1

Now plug in the numbers

d₁ = d₂

v₁t₁ = v₂t₂

60t₁ = 80t₂

60 (t₂ + 1) = 80t₂

60t₂ + 60 = 80t₂

60t₂ - 80t₂ = - 60

-20t₂ = - 60

t₂ = - 60/-20

t₂ = 3

After 3 hours running, the second train will catch up with the first train.

Answer: 3 hours

Should be 3 hrs. when the second train leaves, it is 60 miles away from the first train and the speed difference is 80-60=20MPH, so it takes 60/20 hrs to catch up