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14 September, 10:53

How to solve 9x+5=28

-3x-10y=-26 by Elimination

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Answers (2)
  1. 14 September, 11:19
    0
    So elimination

    I assume that you meant to write

    9x+5y=28 and not 9x+5=28

    so

    elimination is basically eliminating values

    9x+5y=28

    -3x-10y=-26

    we can either cancel out the x terms or the y terms, I will cancel out the y terms

    9x+5y=28

    multipy both sides by 2

    18x+10y=56

    add to other equation

    18x+10y=56

    -3x-10y=-26 +

    15x+0y=30

    15x=30

    divide both sides by 15

    x=2

    subsitute

    9x+5y=28

    9 (2) + 5y=28

    18+5y=28

    subtract 10 from both sides

    5y=10

    divide both sides by 5

    y=2

    x=2

    y=2
  2. 14 September, 12:29
    0
    9x + 5 = 28

    - 5 - 5

    9x = 23

    9 9

    x = 2⁵/₉

    -3 (2⁵/₉) - 10y = - 26

    -7²/₃ - 10y = - 26

    + 7²/₃ + 7²/₃

    -10y = - 18¹/₃

    -10 - 10

    y = 1⁵/₆

    (x, y) = (2⁵/₉, 1⁵/₆)
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