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Mathematics
Roman Dudley
14 September, 10:53
How to solve 9x+5=28
-3x-10y=-26 by Elimination
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Will Holloway
14 September, 11:19
0
So elimination
I assume that you meant to write
9x+5y=28 and not 9x+5=28
so
elimination is basically eliminating values
9x+5y=28
-3x-10y=-26
we can either cancel out the x terms or the y terms, I will cancel out the y terms
9x+5y=28
multipy both sides by 2
18x+10y=56
add to other equation
18x+10y=56
-3x-10y=-26 +
15x+0y=30
15x=30
divide both sides by 15
x=2
subsitute
9x+5y=28
9 (2) + 5y=28
18+5y=28
subtract 10 from both sides
5y=10
divide both sides by 5
y=2
x=2
y=2
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Denzel Graham
14 September, 12:29
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9x + 5 = 28
- 5 - 5
9x = 23
9 9
x = 2⁵/₉
-3 (2⁵/₉) - 10y = - 26
-7²/₃ - 10y = - 26
+ 7²/₃ + 7²/₃
-10y = - 18¹/₃
-10 - 10
y = 1⁵/₆
(x, y) = (2⁵/₉, 1⁵/₆)
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