Expand (x+3) ^6 using Pascal's triangle

The equation that the question is asking to expand the (x+3) ^6 using Pascal's triangle and base on my further computation and further calculation, I would say that the answer would be (x+y) 6 = 1 ⋅ x6 y + 6 ⋅ x5 y1 + 15 ⋅ x4 y2 + 20 ⋅ x3 y3 + 15 ⋅ x2 y4 + 6 ⋅ x1 y5 + 1 ⋅ x y6, I hope you are satisfied with my answer and feel free to ask for more